The pleasure of solving!
It's been a quite long since I blogged something :) May be a writer's block* (*acronym for pure laziness,here);) Well, Last Saturday, I went to dxmk9 program conducted by NSS collage of engineering at Kottamaidhanam, Palakkad. I had registered my name for 'Geek's Paradise' competition which is basically a C programming contest. The first task was to answer some objective questions, mainly to predict the output, was not much tough. The second task was to print a number pattern like this:
1
1 2 1
1 2 3 2 1
1 2 3 4 3 2 1
1 2 3 2 1
1 2 1
1
whooo! the problem was not easy for a newbie like me ('m still in school,sir ;) ), I simply wrote some printf() statements with some ++i,etc. and escaped! Also, I had no much time to think, I had promised to return home before 1 PM.
When I reached home, a sudden thought flashed across my mind "Why shouldn't I give a try ?". I booted my ubuntu system ( 'm eagerly waiting to get Fedora in hands), took newly installed Netbeans IDE and started trying. After some time - LOL :) !! It worked!! The program asked for an integer input and printed the pattern exactly the way it's meant to be! I know, this is a small problem and has nothing of great speciality or something, but don't know why - The output gave me some moments of rejoice! A small pleasure of coding :) Ha ha, I would like to share that code with you :)
/* * 121.c * * Copyright 2009 Ershad K <[email protected]> * * Licensed under GPL Version 3 */ #include <stdio.h> main() { int n; int i = 1; int j = 1; printf("Enter a number: "); scanf("%d",&n); // Increment.... for (;i <= n; i++ ) { for(j = 1; j <= i; j++) { printf(" %d",j); } --j; for (--j; j >=1; j--) { printf(" %d",j); } printf("n"); } // Decrement.... for (i = n-1;i >= 1; i-- ) { for(j = 1; j <= i; j++) { printf(" %d",j); } --j; for (--j; j >=1; j--) { printf(" %d",j); } printf("n"); } } Patches are always welcome :) All the best, nice day!
Leave a Comment